X^2+4x=276

Solution for X^2+4x=276 equation:

X^2+4X=276

We move all terms to the left:

X^2+4X-(276)=0

a = 1; b = 4; c = -276;
Δ = b2-4ac
Δ = 42-4·1·(-276)
Δ = 1120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1120}=\sqrt{16*70}=\sqrt{16}*\sqrt{70}=4\sqrt{70}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{70}}{2*1}=\frac{-4-4\sqrt{70}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{70}}{2*1}=\frac{-4+4\sqrt{70}}{2}
$